Reactive power in AC circuit
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What is meant by reactive power in AC circuits? Power is joules per second.
Real power is the energy dissipated in the resistor per second.
What is meant by the reactive power? Does this mean the energy being stored in capacitor and inductor per second, or does it mean the stored energy supplied per second by the inductor or capacitor.
If we have a voltage source connect with an RLC network and after some time the inductor and capacitor are suddenly detached from the network and then they are supplied to another resistor with diffent value without voltage source then of course they will supply the energy at a new rate to the new resistance depending upon value the resistance. Will this not make the value of stored energy per second different from the value of energy supplied per second? Doesn’t that give two different values of reactive power? Doesn’t this mean that the reactive power is now changed for the same capacitor and inductor?acreactive-powerShareCiteEditFollowFlagedited 15 hours agoJRE47.1k88 gold badges7474 silver badges127127 bronze badgesasked yesterdayAlex61211 gold badge77 silver badges1919 bronze badges
- 1Hmmm are you sure this one isn’t a duplicate? – K H yesterday
- @Transistor, Many thanks for your advice. So I will delete my comments and try to write up an answer later. Cheers. – tlfong01 yesterday
What is meant by reactive power in AC circuits.
- Real power is V⋅I⋅cos(θ)V⋅I⋅cos(θ)
- Reactive power is V⋅I⋅sin(θ)V⋅I⋅sin(θ)
- Apparent power is V⋅IV⋅I (derived from the above using Pythagoras)
Picture from hereShareCiteEditFollowFlaganswered yesterdayAndy aka335k1818 gold badges275275 silver badges584584 bronze badgesAdd a comment5
Capacitors and Inductors are Reactors and account for the reactive power in an AC circuit. When you measure the current and voltage in an AC circuit, you measure what is called Apparent Power, which will appear to be greater than the actual True Power being used in the circuit if the circuit has reactors in it. They store and release energy, causing current to flow in the process even though the Reactive Power isn’t being used and contributing to the “Power” you “see”. To recognise the difference between the energy being stored and being used, we refer to True Power in W(watts), Reactive Power in VAR (volt-amps reactive) and Apparent Power in VA (volt-amps).
The Apparent Power is not simply the sum of the True Power and the Reactive Power. Instead it’s a Pythagorean relationship where the Apparent power is the long side of a square triangle, the True Power is the horizontal line and the Reactive Power is the vertical line. You can apply trigonometric rules and the Pythagorean Theorem to calculate values on different sides of the triangle from your known values.ShareCiteEditFollowFlaganswered yesterdayK H3,55388 silver badges2424 bronze badgesAdd a comment3
Reactive power is a concept that comes out in AC circuits where the voltage or current sources have a sine wave shape with a certain fixed frequency f.
Picture this circuit: a sine wave voltage source V that charges and discharges a capacitor C. They are in parallel.
Vc(t) = V * sin (2 * pi * f * t)
V and f are fixed.
Look at this picture from Wikipedia:
Initially the capacitor is discharged. The current flows from the source to the capacitor. We like that. When Vc reaches its maximum V, the capacitor GIVES BACK the current to the source. The bad thing for the voltage source is that it is receiving current from the capacitor while V is still positive. When V is positive, the voltage source is supposed to push power to the load. Reactive power is the power that the capacitor C returns back to the voltage source.
Power is the blu line in the picture.
It changes in time.
If you take its integrals in the 90-180 and 270-360 intervals you have the reactive power over the period T = 1/fShareCiteEditFollowFlagedited yesterdayanswered yesterdayEnrico Migliore82633 silver badges77 bronze badgesAdd a comment3
“In ac circuits, energy flows into and out of energy storage elements (inductances and capacitances). For example, when the voltage magnitude across a capacitance is increasing, energy flows into it, and when the voltage magnitude decreases, energy flows out. Similarly, energy flows into an inductance when the current flowing through it increases in magnitude. Although instantaneous power can be very large, the net energy transfered per cycle is zero for either an ideal capacitance or inductance.
When a capacitance and an inductance are in parallel energy flows into one, while it flows out of the other. Thus, the power of a capacitance tends to cancel that of an inductance at each instant in time.
The peak instantaneous power associated with the energy storage elements contained in a general load is called reactive power and is given byQ=VRMSIRMS⋅sin(θv−θi)Q=VRMSIRMS⋅sin(θv−θi)
The physical units of reactive power are watts. However, to emphasize the fact that QQ does not represent the flow of net energy, its units are usually given as Volt Amperes Reactive (VARs).”
Importance of reactive power
“Even though no average power is consumed by a pure energy-storage element, reactive power is still of concern to power-system engineers because transmission lines, transformers, fuses, and other elements must be capacble of withstanding the current associated with reactive power. It is possible to have loads composed of energy-storage elements that draw large currents requiring heavy-duty wiring, even though little average power is consumed. Therefore, electric-power companies charge their industrial customers for reactive power as well as for total energy delivered.”
Electrical Engineering Principles and Applications by Allan R. HambleyShareCiteEditFollowFlagedited 12 hours agoanswered yesterdayCarl1,19011 gold badge55 silver badges1919 bronze badges
- Can you please clarify how much of your answer was from this textbook? Did you copy the text or paraphrase? – Elliot Alderson yesterday
- It might be useful to clarify the significance of the sign of reactive power. If a load whose reactive power is positive is connected in parallel with one whose reactive power is negative, one load may use energy it stored during part of each cycle to feed power to the other load which will then store it for later return back to the first load. – supercat yesterday
- Carl – 1. Please provide a weblink to the text. 2. When quoting sources please make it clear which is quotation and which is your material. Use of “quote marks” is a good start. Substantial quotation can be acceptable but in the interests of fair use”, copyright and general information it is desirable for what is what to be clear. – Russell McMahon♦ 12 hours ago
- @RussellMcMahon I have updated my answer. Is it clearer now? – Carl 12 hours ago
- 1Carl – Thanks. Do you have a link? || That indicates that the answer is wholly from the cited text. I’m not meaning to be nitpicking (or a pain 🙂 😦 ) and you can leave it as is or change it as desired but where the material is entirely quoted then stating this at the top gives a clearer indication. – Russell McMahon♦ 12 hours ago
Add a comment+1-2
The OP asks the following questions:
- What is meant by reactive power in AC circuits?
- Real power is the the energy dissipated in the resistor per second. Then what is meant by the reactive power?2.1 Does this mean the energy being stored in capacitor and inductor per second?2.2 Or does it mean the stored energy supplied per second by the inductor or capacitor?
- If we have a voltage source connected with RLC network and after some time the inductor and capacitor are suddenly detached from the network and then they are supplied to another resistor with different value without voltage source then of course they will supply the energy at a new rate to the new resistance depending upon value the resistance.3.1 Will this not make the value of stored energy per second different from the value of energy supplied per second?3.2 And doesn’t that give the two different values of reactive power?3.3 Doesn’t this mean that the reactive power is now changed for the same capacitor and inductor?
Part 1 – A summary of the OP’s questions
The OP is basically asking the following:
- How “Reactive Power” is different from “Real Power”?1.1 About “Real Power” – Is it true that “Real power” is the electrical power which transforms/converts/dissipates electrical energy into to a lower form heat energy absorbed by a resistor, which becomes heated, and then “transfers” its absorbed heat energy to its surrounding air which becomes warmer. In other words, heat energy is not stored but gone forever into the Universe.1.2 About “Reactive Power” – Is it true that “Reactive Power” is the electrical power which converts electrical energy to build up (a) a “magnetic field” around an current flowing inductor, and/or (b) an electric field/potential inside a charged up capacitor?Now, is “Inductive/Magnetic Field Energy” and/or “Capacitive/Electric field energy” never get transformed to a lower/inferior energy. But can they be transformed back to electrical energy? (Note 1)Note 1 – This answer confines to oversimplified RLC power/energy. Therefore, induction motor which indeed can convert magnetic field power/energy to mechanical power/energy is not considered/discussed.
Part 2 – The answer
2.1 What is reacting power?
/ to continue, …
2.2 What happens in the thought experiment of “Inductor and capacitor with stored energy disconnect from current resistor and connect to another new resistor”?
/ to continue, …
(2) Reactive Power Tutorial – Electronics Tutorials
(3) Reactive Power Tutorial – All About Circuits
(4) DC Circuit Text Book, 1st Ed (free eBook) – Chad Davis, Okahoma University
(5) AC Circuit Text Book, 1st Ed (free eBook) – Chat Davis, Okahoma University
Appendix A – Charging a capacitor and Inductor Transient
Appendix B – Energy stored in capacitor and inductor
Appendix C – Reactive Energy Analogy
ShareCiteEditDeleteFlagedited 9 hours agoanswered 16 hours agotlfong011,67811 gold badge66 silver badges1111 bronze badges
- 1Please stop creating long posts, and keep the edits down to less than 5 – Voltage Spike♦ 3 hours ago
- Thank you for your advice. Cheers. – tlfong01 40 secs ago Edit
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